(3x^-8/5y^3)^-2

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Solution for (3x^-8/5y^3)^-2 equation: 


D( x )

((3*x^-8)/5)*y^3 = 0

x = 0

((3*x^-8)/5)*y^3 = 0

((3*x^-8)/5)*y^3 = 0

3/5*x^-8*y^3 = 0 // : 3/5*y^3

x^-8 = 0

x naleu017Cy do O

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(((3*x^-8)/5)*y^3)^-2 = 0

25/9*x^16*y^-6 = 0 // : 25/9*y^-6

x^16 = 0

x = 0

x in { 0} 

x belongs to the empty set

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